pls solve this question
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The given surface is frictionless so no external force is acting on the system. Hence linear momentum of the system will remain conserved.
⇒ Initial momentum = Final momentum
⇒0=60×V+1×12
⇒v=−15m/s (-ve sign show man moves in opposite direction of stone)
Kinetic energy of the boy after separation (K.E.)=12mv2
K.E.=12×60×125
K.E.=1.2J
Hope helps.....
Pls mark brainliest
devanayan2005:
Same answer.....
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