Question

pls solve this question​

Answer 1

Step-by-step explanation:

Polynomials

$a {z}^{3} + 4 {z}^{2} + 3z - 4 \:$

And

${z}^{3} - 4z + a$

leave the same remainder when divided by (z-3). Substitute z=3 in both these polynomials, we get

$a {(3)}^{3} + 4 {(3)}^{2} + 3(3) - 4 =$

${(3)}^{3} - 4(3) + a = > 27a + 41 =$

$15 + a = > 27a - a = 41 - 15 = >$

$26a = 26 = > a = 1$

Hope it helps you.