Question

pls.solve this question​

Answer 1

Answer:

( 4a+5b+14)(2a+3b+8)

Step-by-step explanation:

8(a+1)^2+2(a+1)(b+2)-15(b+2)^2 =

let a+1 =p and b+2=q

then the given equation will become,8p^2+2pq-15q^2

= 8p^2+12pq-10pq-15q^2

=(4p+5q)(2p+3q); On re substituting the values of p and q

= [4(a+1)+5(b+2)][2(a+1)+3(b+2)]

=( 4a+5b+14)(2a+3b+8)