pls solve this....question
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Answer:
i) 1.3333 m/s
ii) 0 m/s
iii) -1.3333 m/s
Explanation:
=> To be known,
Velocity = ∆d/∆t
= change in displacement/change in time
Getting data from graph
i) d1 = 0 m
d2 = 4 m
∆d = d2 - d1 = 4-0 = 4 m
t1 = 2 sec
t2 = 5 sec
∆t = t2 - t1 = 5-2 = 3 sec
velocity = ∆d/∆t = 4/3 = 1.3333 m/s
ii) d1 = 4 m
d2 = 4 m
∆d = d2 - d1 = 4- 4= 0 m
t1 = 5 sec
t2 = 7 sec
∆t = t2 - t1 = 7 - 5 = 2 sec
velocity = ∆d/∆t = 0/3 = 0 m/s
iii) d1 = 4 m
d2 = m
∆d = d2 - d1 = 0-4 = -4 m
t1 = 7 sec
t2 = 10 sec
∆t = t2 - t1 = 10- 7= 3 sec
velocity = ∆d/∆t = -4/3 = -1.3333 m/s
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