pls solve this question
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AS when you must be knowing that (x^a)^a+b=x^a(a+b)
and when you write that and open the brackets you will see that every first power will be cancelled and then x^a+b will be there in bothe numerator and the denominator and x^b+c will also be the same and so will x^c+a and then all of that will become 1 and then you will get 1 as your answer
AS when you must be knowing that (x^a)^a+b=x^a(a+b)
and when you write that and open the brackets you will see that every first power will be cancelled and then x^a+b will be there in bothe numerator and the denominator and x^b+c will also be the same and so will x^c+a and then all of that will become 1 and then you will get 1 as your answer
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