pls solve this question.
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Explanation:
Assume the initial velocity or height of first green line is u and acceleration is a.
next 3 green lines height will be
u+5a ,u+8a ,u+10a
area of a trapezoid
1/2(sum of parallel lines)(height)
given
1/2(2u+5a)5=10 and 1/2(2u+13a)3=20
or 2u+5a=4 and 6u+39a=20
we get u=7/6 and a = 1/3
Area of last trapezoid = 1/2(2u+18a).2=7/3+6=25/3=8.3
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