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By using completing the square method we have two values of x .
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Answer:
given QE=x^2+4x-1412
x=(-b±√b^2-4ac)/2a
here b=4,a=1,c=-1412
∴(-4±√(-4)^2-4*1*-1412)/2*1
=(-4±√16+5648)/2
(-4±√5664)/2
(-4±4√354)/2
(-4+4√354)/2 or (-4-4√354)/2
-2+2√354 or -2-2√354
please mark it as brainliest
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