pls solve this question
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Answer: 0.54 sec
distance*2 = speed * time
( it must have to cover twice the distance as sound have to hit the wall and come back)
time=2*distance/ speed
put individual distance
and speed= 330 m/s
case1: T1 = (2* 130)/330 = 0.78 sec
case 2: T2 = (2*40)/330 = 0.24 sec
ttime between 2 echos = 0.78-0.24 = 0.54sec
Answered by
0
Answer is 0.54second
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