Question

Pls solve this question!! ​

Answer 1

Answer:

25 is equal

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\sqrt{x} + \sqrt{x - \sqrt{1 - x} } = 1 \\ squaring \: on \: both \: side \\ x + x \sqrt{1 - x} = 1 \\x \sqrt{1 - x} = 1 - x \\ \sqrt{1 - x} = \frac{1 - x}{x} \\ squaring \: on \: both \: side \\ 1 - x = \frac{1 - {x}^{2} }{ {x}^{2} } \\ 1 - x = \frac{1}{ {x}^{2} } - \frac{ {x}^{2} }{ {x}^{2} } \\ 1 - x = \frac{1}{ {x}^{2} } - 1 \\ 2 = \frac{1}{ {x}^{2} } - x \\ 2 {x}^{2} + x = 1 \\ 2 {x}^{2} + x - 1 = 0$