Question

pls solve this question​

Answer 1

Answer:

(8.1 ± 0.3 gcm -3)

Explanation:

let the measured values be:

mass of the block = 39.3 g

length of block = 5.12 cm

breadth of block= 2.56 cm

thickness of the block = 0.37 cm

the density of the block is given by p= mass/volume= m/l x b x t

                                                          39.3 g/(5.12 x 2.56 x 0.37)cm

                                                          =  8.1037 gcm -3

now uncertainly in m = ±0.1 g

uncertainly in l = ±0.01 cm

uncertainly in b = ±0.01 cm

uncertainly in t = ±0.01 cm

maximum relative error , in the density value is therefore, given by

Δp/p = Δl/l+Δb/b+Δt/t+Δm/m

        = 0.01/5.12 + 0.01/2.56 + 0.01/2.37 + 0.1/39.3

        = 0.0019 + 0.0039 + 0.027 + 0.0024

         = 0.0358

hence    p= 0.0358 x 8.1037 ≈ 0.3 gcm -3

we cannot therefore report the calculated value of p (=8.1037 gm -3 ) up to the fourth decimal place. ∵p=0.3 gcm -3  the value of p can be regarded as accurate up to the first decimal place only. hence the value of p must be rounded off to as 8.1 gcm -3 and the result of the measurements should be reported= (8.1 ±0.3 gcm -3).

Answer 2

Answer:

no.. i have not a in box power