Math, asked by bhakti34, 10 months ago

pls solve this question ​

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Answers

Answered by saikiajita609
1
  1. (1) 5x–4x2+3

when x=0

5(0)-4(0)2+3

0-0+3

3

(2)when x=-1

5x-4x2+3

5(-1)-4(-1)2+3

-5-4+3

-6

(3)when x=2

5x-4x2+3

5(2)-4(2)2+3

10-16+3

-6+3

-3

Hope it will help you

please mark as BRAINLIEST

Answered by aryan1234243
0

Step-by-step explanation:

1) 5x-4x²+3

x=0

5(0)-4(0)²+3=3

x=-1

5(-1)-4(-1)²+3

-5-4+3=-9+3=-6

x=2

5(2)-4(2)²+3

10-16+3=-3

2)p(y)=y²-y+1

p(0)=(0)²-(0)+1=1

p(1)=(1)²-(1)+1=1

p(2)=(2)²-(2)+1=4-2+1=3

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