Question

pls solve this question... ​

Answer 1

Answer:

0

Step-by-step explanation:

Let

$(2 - a) = x$

$(2 - b) = y$

$(2 - c) = z$

Now the expression converts to

${x}^{3} + {y}^{3} + {z}^{3} - 3xyz$

${x}^{3} + {y}^{3} + {z}^{3} - 3xyz = (x + y + z)( {x}^{2} + {y}^{2} + {z}^{2} - xy - yz - zx)$

Now,

$x + y + z = (2 - a) + (2 - b) + (2 - c) = 6 - (a + b + c) = 6 - 6 = 0$

Therefore,

${x}^{3} + {y}^{3} + {z}^{3} - 3xyz = 0$