Math, asked by Jackfroster, 1 year ago

pls solve this question 2 tan^-1 (A)=

Answers

Answered by golu46
1
diff w r t x
d/dx(2tan^-1(A))
=0 bcoz derivative of constant is o
A is not variable so we cant diff w r t A.
A is constant
it will useful to u...plz mark
Answered by Ruhanika105
5
Hey friend, ☺

*1). 2 tan^-1 (A) = sin^-1 [2(A) / (1+A^2)] ,where |A|<=1.

*2). 2 tan^-1(A) = cos^-1 [ (1-A^2) / (1+A^2)], where A >=0.

*3). 2 tan^-1(A) = tan^-1 [ (2A/1-A^2)], where -1 <A<1.

Proof:

(1).
Let tan^A = y. Now,
sin^-1 [ (2A/ 1+A^2)]
= sin^-1 [ 2 tany/(1+tan^2y) ]
=sin^-1 (sin2y)
= 2y
= 2 tan^-1(A).

(2).
Also, cos^-1 [(1-A^2) / (1+A^2)]
= cos ^-1 [ (1-tan^2y) / (1+tan^2y)]
=cos^-1 (cos2y)
= 2y
=2tan^-1 (A)

Similarly 3rd can be worked out.

☺ HOPE IT HELPS YOU!!!!! ☺


Ruhanika105: If my answer helped you friend, plz mark the brainliest!!!
golu46: que is to solve ,not to prove
golu46: i think h
Ruhanika105: Yah sorry for tht
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