pls solve this question
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Solution....
x^4 - 256
= (x^2) ^2 -(16) ^2
= (x^2 -16) (x^2+16)
= (x^2-4^2) (x^2+16)
= (x-4) (x+4) (x^2+16)
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Rewrite x4 as (x2)2 ( x 2 ) 2 . Rewrite 256 as 16^2 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 - b 2 = ( a + b ) ( a - b ) where a=x2 a = x 2 and b=16 .Thanks . Bye . Have a nice day
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