Question

pls solve this question

Answer 1

Heya friend!!!
this is the solution.....
hope it helps u..... :)

Answer 2

In the quadrilateral ABCD,
ar(ABCD)= ar(∆ADC) + ar(∆ABC)
Now,
In ∆ADE,
ar(∆ADE) = ar(∆ADC) + ar(∆ACE)
Now,
ar(∆ABC) = ar(∆ACE),
because these two triangles are on same base(AC) and between parallel (AC ll BE).
So,
ar(∆ADC) + ar(∆ABC) = ar(∆ADC) + ar(∆ACE)
Therefore,
ar(ABCD) = ar(∆ADE)




Hope it may help you
Have a good day!!!!!