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Draw a line parallel DC and BA and let the line
be XY
Such that XY || AB II CD
Since they r parallel,
In AB II XY
LABE + L BEY = 180°
110 + L BEY = 180°
L BEY = 70° -------- (1)
In CD || XY
L DCE + L CEX = 180°
130° + L CEX = 180°
L CEX = 50° ---------(2)
Now,
CEX + L CAN + L BEY = 180° ( linear pair ) L
50° + L CEB + 70° = 180°
120° + L CEB = 180°
L CEB = 60°
==> L BEC = 60°
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