Question

Pls solve this question​

Answer 1

QUESTION⤵️

$If \: {x}^{2} + \frac{1 }{ {x}^{2} } = 62 \: then \: find \: x + \frac{1}{x}$

ANSWER⤵️

$\: {x}^{2} + \frac{1 }{ {x}^{2} } = 62 \:$

ADD 2 BOTH THE SIDES

$\: {x}^{2} + \frac{1 }{ {x}^{2} } + 2 = 62 \: + 2$

$\: {x}^{2} + \frac{1 }{ {x}^{2} } + 2 \times {x}^{2} \times \frac{1}{ {x}^{2} } = 62 \: + 2$

${(x + \frac{1}{x}) }^{2} = 64$

${(x + \frac{1}{x}) }^{2} = {8}^{2}$

${(x + \frac{1}{x}) } = \: plus \: minus \: 8$

${(x + \frac{1}{x}) } = + 8 \: or \: - 8$

BE BRÃÎÑLY♡

$\huge\star\mathcal\pink{hope \: it \: helps}\star$