Question

pls solve this question

Answer 1

kx^2 + 3k + 2x

Comparing with std equation

ax^2 + bx + c

We get,
a=k
b=2
c=3k

Sum of roots = -b/a = -2/k
Product of roots = c/a= 3

ATQ:
-2/k=3
Therefore, k=-2/3

Answer 2

Hey mate !!!


here is your answer !!!



a = K




b = 2




c = 3k





let the zeroes of polynomial be
$\alpha \: \: and \: \beta = - b \div a$
=> -2 / k --------------------(1)

product =
$\alpha \beta$

c/a

=> 3k / k






now ,


sum is equal to PRODUCT


we get




$\alpha \beta = \alpha \: + \beta$


3 = -2 / k



k = > -2 / 3





hope it helps you dear !!!



thanks !!!