Question

pls solve this question.​

Answer 1

Ur answer to the question in attachment:

$\frac{4yz( {z}^{2} + 6z - 16) }{2y(z + 8)} \\ = \frac{4yz(z + 8)(z - 2)}{2y(z + 8)} \\ = 2z(z - 2) \\ = 2 {z}^{2} - 4z$

My coding was wrong so i spammed there;i was writting my Answer in correct order nd u reported it!):