Math, asked by Jacksepticeyefan, 4 months ago

pls solve this question.

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Answered by Anonymous

28

Ur answer to the question in attachment:

$\frac{4yz( {z}^{2} + 6z - 16) }{2y(z + 8)} \\ = \frac{4yz(z + 8)(z - 2)}{2y(z + 8)} \\ = 2z(z - 2) \\ = 2 {z}^{2} - 4z$

My coding was wrong so i spammed there;i was writting my Answer in correct order nd u reported it!):

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