Question

Pls solve this question

Answer 1

answer:-1

hope this helps u

Answer 2

Given :

$\boxed{\bf\dfrac{4x+7}{9-3x}=\dfrac{1}{4}}$

To Find :

The value of x.

Solution :

Analysis :

Here we have to solve the equation using suitable signs and identities.

Explanation :

$\\ \Rightarrow\sf\dfrac{4x+7}{9-3x}=\dfrac{1}{4}$

By cross multiplying,

$\\ \Rightarrow\sf4(4x+7)=1(9-3x)$

Expanding the brackets,

$\\ \Rightarrow\sf16x+28=9-3x$

Transposing -3x to LHS and 28 to RHS,

$\\ \Rightarrow\sf16x+3x=9-28$

After evaluation,

$\\ \Rightarrow\sf19x=-19$

$\\ \Rightarrow\sf x=\dfrac{-19}{19}$

$\\ \Rightarrow\sf x=\cancel{\dfrac{-19}{19}}$

$\\ \Rightarrow\sf x=-1$

$\\ \therefore\boxed{\bf x=-1.}$

The value of x is -1.

Verification :

LHS :

$\\ \Rightarrow\sf\dfrac{4x+7}{9-3x}$

• Putting x = -1,

$\\ \Rightarrow\sf\dfrac{4(-1)+7}{9-3(-1)}$

$\\ \Rightarrow\sf\dfrac{(4\times(-1))+7}{9-(3\times(-1))}$

$\\ \Rightarrow\sf\dfrac{-4+7}{9-(-3)}$

$\\ \Rightarrow\sf\dfrac{3}{9+3}$

$\\ \Rightarrow\sf\dfrac{3}{12}$

$\\ \Rightarrow\sf\cancel{\dfrac{3}{12}}$

$\\ \Rightarrow\sf\dfrac{1}{4}$

$\\ \therefore\boxed{\bf LHS=\dfrac{1}{4}}.$

RHS :

$\\ \therefore\boxed{\bf RHS=\dfrac{1}{4}}.$

LHS = RHS.

• Hence verified.