Question

pls solve this question...

Answer 1

Answer:

area of shaded rectangle is = 28$cm^{2}$

Step-by-step explanation:

Area of the parallelogram = base x height

bh = 40$cm^{2}$

given base = 10cm

=> height = 40$cm^{2}$ / 10 cm = 4cm.

so from the right angled triangle in the parallelogram, we have hypotenuse = 5 cm and one side is 4cm.

so by pythagorean theorem, value of other side is

$5^{2} = x^{2} + 4^{2} \\=> x^{2} = 25 - 16\\=>x^{2} =9\\=> x = 3$

method 1:

now length of rectangle = 10cm - 3cm = 7cm.

and we know breadth (height) = 4 cm

area of rectangle = length x breadth

area of shaded rectangle = 7cm x 4 cm = 28$cm^{2}$.

method 2:

so area of triangle is

=  $\frac{1}{2} (base)x(height)$

= $\frac{1}{2}$*3*4 = 6$cm^{2}$

now area of shaded rectangle is = area of parallelogram - 2(area of triangle)

area of shaded rectangle = 40$cm^{2}$ - 2(6$cm^{2}$) = 40$cm^{2}$ - 12$cm^{2}$ = 28$cm^{2}$.

Answer 2

Answer:

Given area of parallelogram = area of rectangle

area of rectangle = 40×12cm2

Area = 480cm2

Let 'h' be height of 11 gm 

then

Area = 21×base×height=21×h×16=480

h=16480×2=60cm

∴ Height of parallelogram is 60 cm.

Step-by-step explanation:

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