Math, asked by poonamteach26, 5 hours ago

pls solve this question

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Answered by himanipt7
4

Answer:

Step-by-step explanation:

\frac{5+3\sqrt{3} }{7+4\sqrt{3} }

=\frac{5+2\sqrt{3}  }{7+4\sqrt{3} }\times\frac{7-4\sqrt{3} }{7-4\sqrt{3} }

=\frac{(5+2\sqrt{3})(7-4\sqrt{3})  }{(7)^{2}-(4\sqrt{3} )^{2}  }

=\frac{5(7-4\sqrt{3})+2\sqrt{3}(7-4\sqrt{3} )  }{49-48}

=35-20\sqrt{3} +14\sqrt{3}-24

=11-6\sqrt{3}

=11-6\times1.732

=11-10.392

=0.608

Answered by ravneet130106
0

Answer:

your ans

hope it will help you

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