Question

pls solve this question
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Answer 1

Answer:

Step-by-step explanation:

$\frac{5+3\sqrt{3} }{7+4\sqrt{3} }$

$=\frac{5+2\sqrt{3} }{7+4\sqrt{3} }\times\frac{7-4\sqrt{3} }{7-4\sqrt{3} }$

$=\frac{(5+2\sqrt{3})(7-4\sqrt{3}) }{(7)^{2}-(4\sqrt{3} )^{2} }$

$=\frac{5(7-4\sqrt{3})+2\sqrt{3}(7-4\sqrt{3} ) }{49-48}$

$=35-20\sqrt{3} +14\sqrt{3}-24$

$=11-6\sqrt{3}$

$=11-6\times1.732$

$=11-10.392$

$=0.608$

Answer 2

Answer:

your ans

hope it will help you