Question

pls solve this question​

Answer 1

$[\frac{-1}{6} +(\frac{3}{2})^{-1} ]^{-1}\\\\= [\frac{-1}{6} +\frac{2}{3}]^{-1}\\\\= [\frac{-1+4}{6}]^{-1}\\\\= [\frac{3}{6}]^{-1}\\\\= [\frac{1}{2}]^{-1}\\\\= 2$

#Property used : $(\frac{a}{b})^{-1} = \frac{b}{a}$.

pls mark as brainliest as it took so much time to write with math input! :D