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given d= 0.5 mm
a hence , r=d/2 = 0.5/2 = 0.25 mm
= 2.5 ×10^-4 rho= 1.6 ×10^-8 ohm m
R=10 ohm and L =?
R=rho L/A = L= (2.5 ×10^-4 )2/1.6× 10^-8 = 122.76 m
bgiven d= 1mm or R = 0.55mm = 5 × 10 ^-4 = 1.6 ×10^-8 × 122.76/ 3.14 × (5×10^-4)-2 =2.5 ohm
a hence , r=d/2 = 0.5/2 = 0.25 mm
= 2.5 ×10^-4 rho= 1.6 ×10^-8 ohm m
R=10 ohm and L =?
R=rho L/A = L= (2.5 ×10^-4 )2/1.6× 10^-8 = 122.76 m
bgiven d= 1mm or R = 0.55mm = 5 × 10 ^-4 = 1.6 ×10^-8 × 122.76/ 3.14 × (5×10^-4)-2 =2.5 ohm
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answer is in the above picture.
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