Question

pls solve this question​

Answer 1

Answer:

$\sqrt[4]{mn}$

Step-by-step explanation:

Given,

tan θ + sin θ = m

tan θ – sin θ = n

m2 – n2 = (tan2θ + sin2θ + 2 tan θ sin θ) – (tan2θ + sin2θ – 2 tan θ sin θ)

= 4 tan θ sin θ….(i)

mn = (tan θ + sin θ)(tan θ – sin θ)

= tan2θ – sin2θ

= (sin2θ/cos2θ) – sin2θ

= sin2θ(sec2θ – 1)

mn = sin2θ tan2θ

Taking square root on both sides,

√mn = sin θ tan θ….(ii)

From (i) and (ii),

m2 – n2 = 4√mn

please... mark me brainliest also

Answer 2

I hope it is helpful to you

and hope u understand easily.