Question

Pls solve this question.

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Answer 1

Solution:

We have to factorise the given polynomial.

= (2x - y)² - 14x + 7y - 18

Can be written as:

= (2x - y)² - 7(2x - y) - 18

For simplicity, let us assume that:

→ u = 2x - y

Then, the expression becomes:

= u² - 7u - 18

Now, 18 can be factored into 9 × 2. So, our expression can be written as:

= u² - (9 - 2)u - 18

= u² - 9u + 2u - 18

= u(u - 9) + 2(u - 9)

= (u + 2)(u - 9)

Substituting back u = 2x - y, we get:

= (2x - y + 2)(2x - y - 9)

★ Hence, the factorised form of the expression is (2x - y + 2)(2x - y - 9)

Answer:

• Factorisation of (2x - y)² - 14x + 7y - 18 is (2x - y + 2)(2x - y - 9)

Answer 2

$\sf{\underline{Question:}}$

Factorise $(2x - y)^{2} - 14x + 7y - 18$

$\sf{\underline{Solution:}}$

$(2x - y)^{2} - 14x + 7y - 18$

$= (2x - y)^{2} - 7(2x - y) - 18$

Let $2x - y$ be $a$

$\implies{a² −9a + 2a − 18}$

$\implies{a(a - 9) + 2(a - 9)}$

$\implies{(a - 9)(a + 2)}$

Putting the value of $a$

$\bold{\red{\implies{(2x - y - 9)(2x - y + 2)}}}$

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