Question

pls solve this question

Answer 1

${(x + \frac{1}{x} )}^{2} = {x}^{2} + 2 \times x \times \frac{1}{x} + \frac{1}{ {x}^{2} } \\ {(4 + 3 + \frac{1}{4 + 3}) }^{} = {x}^{2} + \frac{1}{ {x}^{2} } + 2 \\ 7 + \frac{1}{ 7} - 2 = {x}^{2} + \frac{1}{ {x}^{2} } \\( 49 + 1 )\div 7 - 2= {x}^{2} + \frac{1}{ {x}^{2} } \\ 5+ \frac{1}{7} = {x}^{2} + \frac{1}{ {x}^{2} }$
hope it helps