Question

pls solve this question

Answer 1

Area of trapezium=1/2 × Sum of parallel sides × Distance between them

⇒1/2×30×8

⇒120 m²

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Answer 2

Heya mate,Here is ur answer

Given : Parallel sides of trapezium = 10 and 20 m

Distance b/w them=8 m

So,height of the trapezium = 8 m

We know that

Area of trapezium=1/2×(sum of parallel sides)×height


$= \frac{1}{2} \times (10 + 20) \times 8$


$= \frac{1}{2} \times 30 \times 8$


$= 15 \times 8$


$= 120 \: m {}^{2}$


$<b>So,area of trapezium=120 m^2 </b>$

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✔A trapezium is a quadrilateral in which only one pair of opposite sides are parallel.



✔The perpendicular distance between two parallel sides of a trapezium is its height.



✔Area of trapezium=1/2×(sum of parallel sides)×height

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