pls solve this question
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hariharan108:
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Answer:
Option(A)
Step-by-step explanation:
Given Equation is x + (1/x)² = 3.
⇒ x + (1/x) = √3
On cubing both sides, we get
⇒ (x + 1/x)³ = (√3)³
⇒ x³ + (1/x³) + 3 * x * 1/x(x + 1/x) = 3√3
⇒ x³ + (1/x³) + 3(√3) = 3√3
⇒ x³ + 1/x³ = 3√3 - 3√3
⇒ x³ + 1/x³ = 0
⇒ x⁶ + 1 = 0
⇒ x⁶ = -1.
Now,
x¹⁸ + x¹² + x⁶ + 1
= x¹²(x⁶ + 1) + x⁶ + 1
= x¹²(0) + -1 + 1
= 0.
Therefore, x¹⁸ + x¹² + x⁶ + 1 = 0.
Hope it helps!
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