Math, asked by hariharan108, 1 year ago

pls solve this question

Attachments:

Answers

Answered by sanjay270899
1
Answer is x^0

Method

 = \frac{ {x}^{a + b} \: {x}^{b + c} \: {x}^{c + a} }{ { ({x}^{a} {x}^{b} {x}^{c}) }^{2} }

 = \frac{ {x}^{a + b} \: {x}^{b + c} \: {x}^{c + a} }{ {x}^{2a} \: {x}^{2b} \: {x}^{2c} }

 = \frac{ {x}^{a} {x}^{b} \: {x}^{b} {x}^{c} \: {x}^{c} {x}^{a} }{ { {x}^{2a} \:{x}^{2b} \:{x}^{2c} }}

 = \frac{ {x}^{2a} {x}^{2b} {x}^{2c} }{ { {x}^{2a} \:{x}^{2b} \:{x}^{2c} }}

 = \frac{ {x}^{2a+2b+2c}}{ {x}^{2a+2b+2c}}

 = {x}^{0}
Similar questions