Question

pls solve this question

Answer 1

First the cross multiplication.
9(3k+5) = 4(4k-3)
27k+45 =16k-12
27k-16k = -45-12
11k= -57
k=-57/11

I hope my answer help to u and right

Answer 2

Q•1}

$\bf\frac{3k + 5}{4k - 3} = \frac{4}{9} \\ \\ \sf(solve \: by \: cross \: multiplication) \\ \\ \bf \: = > 9(3k + 5) = 4(4k - 3) \\ \\ \sf (open \: the \: brackets \: and \: multiply \: the \: terms) \\ \\ \bf = > 27k + 45 = 16k - 12 \\ \\ \sf(take \: the \: like \: terms \: to \: one \: side) \\ \\ \bf = > 27k - 16k = - 12 - 45 \\ \\ \bf = > 11k = - 57 \\ \\ \bf = > k = \frac{ - 57}{11}$

$\therefore$Value of k is $\huge{\frac{-57}{11}}$