Pls solve this question
Electricity
Class 10
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Part 1:
Let R be the resistance of the electric lamp. In series total resistance = 5 + R
I = V/R
1 = 10/ 5+R
R = 5 ohm
Part 2:
Total Resistance = 5 ohm
I = 2 A
Current in each branch = 2 / 2 = 1 Amp (since both branches have same resistances, current divides equally)
V across Lamp + conductor = 10 V
V across Lamp = I × R = 1 * 5 = 5 Volt
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I hope it can help you
plzz
regards me
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