Question

pls solve this question fast

Answer 1

Apply the formula of sine inverse x.
Answer is sine inverse root x

Answer 2

Hi ..dear..
here is your answer!!!
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.∵ y = sinֿ¹ [ x.√(1-x) - √x. √(1-x²) ]

∴ y = sinֿ¹ [ (x). √(1-(√x)²) - √x. √(1-(x)²) ] ....... (1)
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Let : (x) = sin α and √x = sin ß. .................... (2)

Then, from (1),

y = sinֿ¹ [ sin α. √(1-sin² ß) - sin ß. √(1-sin² α) ]

. = sinֿ¹ [ sin α. cos ß - sin ß. cos α ]

. = sinֿ¹ [ sin ( α+ß ) ]

. = α + ß

. = sinֿ¹ x + sinֿ¹ √x ............. from (2..
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.hope it helped you!!!
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