Math, asked by nidhikansalin, 10 months ago

pls solve this question I cant get it​

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Answered by ItSdHrUvSiNgH
4

Step-by-step explanation:

 \huge\blue{\underline{\underline{\bf Question:-}}}

The length of the sides of two square fields are in ratio 3:5.The area of larger field is 567 cm² greater than smaller field. Find the ratio of the smaller field.

 \huge\blue{\underline{\underline{\bf Answer:-}}}

  • We know that,

Area = (side)²

So, Now let's take condition of the ratio..

 \\ \\ \frac{side \: \: 1}{side \: \: 2} = \frac{3}{5} \\ \\ \boxed{ side \: \: 1 = \frac{3}{5} \times \: side \: \: 2 } \\ \\ Area \: 1 = {(side \: 1 )}^{2} \\ \\ Also,  \: Area \: \: 2 = 576 + Area \: \: 1 \\ \\ \implies {(side \: 2)}^{2} = 576 + {(side \: \: 1)}^{2} \\ \\ \implies {side \: 2}^{2} = 576 + \frac{9}{25} \times {(side \: 2)}^{2} \\ \\ \implies 25 {(side \: \: 2) }^{2} = 14400 + 9{(side \: \: 2)}^{2} \\ \\ \implies  16{(side \: \: 2)}^{2} = 14400 \\ \\ Taking \: \: square \: \: root... \\ \\ \implies \boxed{  side \: \: 2 = 30 \: m} \\ \\ \\ Also, \\ \\ \implies side \: 1 = \frac{3}{5} \times side \: \: 30 \\ \\ \implies side \: 1 = \frac{90}{5} \\ \\  Area \: of \: smaller \: field \: is \implies \\ \\ \implies {side \: \: 1}^{2} \\ \\ \implies {(18)}^{2} \\ \\ \implies \huge\boxed{ 324 \: \: {m}^{2}} \\

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