Question

pls solve this question I'll really mark it as brainliest(ques 13 1st one)

Answer 1

$log(x + 1) + log(x - 1) = log(11) + 2 log(3) \\ log(x + 1)(x - 1) = log(11) + log( {3}^{2} ) \\ log( {x}^{2} - 1 ) = log(11 \times 9) \\ log( {x}^{2} - 1 ) = log(99) \\ {x}^{2} - 1 = 99 \\ {x}^{2} = 100 \\ x = + - 10 \\ but \: x - 1 \: or \: x + 1 \: cannot \: be \: negative \\ so \: x = 10$
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Answer 2

using loga + logb = log(ab),
log(x^2-1) = log(11 x 9)
removing log,
x^2 - 1 = 99
x^2 = 100
x = 10