Question

pls solve this question..it is quadractic equation​

Answer 1

Answer:

Step-by-step explanation:

Given sum of two numbers is 9

Let one number be x

Another number be 9-x

18 times sum of their reciprocals is 9

18(1/x+1/9-x)=9

18(9-x+x/x(9-x)=9

9/9x-x^2=1/2. [9/18=1/2]

9x-x^2=18

x^2-9x+18=0

x^2-3x-6x+18=0

x(x-3)-6(x-3)=0

(x-6)(x-3)=0

x-6=0 or x-3=0

x=6 or x=3

Therefore,

The two numbers are

One number=x=6

Another number=9-x=9-6=3

Another number=3

HOPE IT HELPS YOU...........