Question

pls solve this question! No spammers please . earn it with a correct explanation . Best explanation will be marked brainliest . I NEED A STEP BY STEP EXPLANATION PLEASE. ​ class 11​

Answer 1

Answer:

Answer:

hey!

the answer is in picture

Answer : To prove : tan A/1-cot A + cot A/1-tan A=1+tan A+cot A

taking L.H.S

= [ tan(A) / (1 - cot(A)) ] + [ cot(A) / (1 - tan(A) ) ]

= [ sin(A)/cos(A) / (1 - cos(A)/sin(A)) ] + [ cos(A)/sin(A) / (1 - sin(A)/cos(A) ) ]

{using tan x = sinx /cos x and cotx = cosx/sinx }

= [ sin(A)/cos(A) / (sin(A)/sin(A) - cos(A)/sin(A)) ] + [ cos(A)/sin(A) / (cos(A)/cos(A) - sin(A)/cos(A) ) ]

= [ sin(A)/cos(A) / (sin(A) - cos(A)) / sin(A) ] + [ ( cos(A)/sin(A) / ( cos(A) -sin(A) ) / cos(A) ) ]

= [ sin(A)sin(A) / cos(A)(sin(A) - cos(A)) ] + [ ( cos(A)cos(A) / sin(A)( cos(A) -sin(A) ) ]

=[ sin2(A) / cos(A)(sin(A) - cos(A)) ] + [ cos2(A) / -sin(A)( sin(A) - cos(A) ) ) ]

=[ sin2(A) / cos(A)(sin(A) - cos(A)) ] - [ cos2(A) / sin(A)( sin(A) - cos(A) ) ) ] ===> LCD

= [ sin2(A) sin(A) / cos(A)sin(A)(sin(A) - cos(A)) ] - [ cos2(A) cos(A) / sin(A)cos(A)( sin(A) - cos(A) ) ) ]

= [ sin3(A) / cos(A)sin(A)(sin(A) - cos(A)) ] - [ cos3(A) / sin(A)cos(A)( sin(A) - cos(A) ) ) ]

=[ sin3(A) - cos3(A) ] / [ sin(A)cos(A)( sin(A) - cos(A) ) ) ]

=[ (sin(A) - cos(A)) ( sin2(A) + sin(A) cos(A) + cos2(A) ) ] / [ sin(A)cos(A)( sin(A) - cos(A) ) ) ]

= [ ( sin2(A) + cos2(A) + sin(A) cos(A) ] / [ sin(A)cos(A) ]

= [ sin2(A) / sin(A)cos(A) ] + [ cos2(A) / sin(A)cos(A) ] + [ sin(A) cos(A) / sin(A) cos(A) ]

= [ sin(A) / cos(A) ] + [ cos(A) / sin(A) ] + 1

= tan(A) + cot(A) + 1

{we know sin x/ cos x = tan x and cos x/sin x = cot x }

= R. H . S

Hence proved

Step-by-step explanation:

Hence proved

Answer 2

Answer:

The answer is (b) t4>t3>t1>t2

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