Question

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Answer 1

EXPLANATION

Question

3(sinx - cosx)^4 + 6(sinx + cosx) ^2 + 4(sin^6x +cos^6x)

TO FIND VALUE OF EQUATION

Let we can assume that a1, a2, a3 are three

value denotes the equation

Let a1 =

3(sinx - cosx) ^4 = 3[(sinx - cosx)^2]^2

3(sin^2x + cos^2x - 2sinxcosx)^2

3(1 - 2sinxcosx)^2

3(1 + 4sin^2xcos^2x - 4sinxcosx)

Let a2 =

6(sinx + cosx)^2

6(sin^2x + cos^2x + 2sinxcosx )

6(1 + 2sinxcosx )

Let a3 =

4(sin^6x + cos^6x )

4(sin^2x + cos^2x)( sin^4x + cos^4x - sin^2xcos^2x)

4[(sin^2x + cos^2x )^2 - 2sin^2xcos^2x - sin^2xcos^2x ]

4(1 - 3sin^2xcos^2x )

Therefore,

sum of a1 + a2 + a3

3 + 6 + 4 = 13 = ANSWER

Answer 2

Answer:

let a³

= 4(sin^6x + cos^6x)

= 4[(sin²x + cos²x )² - 2sin²x cos²x - sin²x cos²x]

Therefore,

Sum of a¹ + a² + a³

= 3 + 6 + 4

= 13

Hope it will be helpful ✌️