Question

Pls solve this question step by step......

Answer 1

Answer:

Step-by-step explanation:

first rationalize all three terms one by one

4√3/(2-√2) × ((2+√2)/(2+√2))

=4√3 + 2√6

30/(4√3-3√2)×((4√3+3√2)/(4√3+3√2))

=4√3+3√2

3√2/(3+2√3) × ((3-2√3)/(3-2√3))

=-3√2+2√6

now algebraic sum of all three terms is

= (4√3 + 2√6) - (4√3+ 3√2) - (-3√2 + 2√6)

=  4√3 + 2√6 - 4√3 - 3√2 + 3√2 - 2√6

= 0