Question

pls solve this question using RHS​

Answer 1

Answer:

hey mate

plz refer to the pic

and plz mark it as brainliest answer

Answer 2

Theta us written as A.

Answer:

( 1 - sinA ) / ( 1 + sinA ) = ( secA - tanA )^2.

Step-by-step explanation:

= > ( 1 - sinA ) / ( 1 + sinA )

= > $\dfrac{1-sinA}{1+sinA}\times\dfrac{1-sinA}{1-sinA}$

= > ( 1 - sinA )^2 / ( 1 - sin^2 A ) { since, ( a - b )( a + b ) = a^2 - b^2, ( 1 + sinA )( 1 - sinA ) = 1 - sin^2 A }

= > ( 1 - sinA )^2 / cos^2 A { 1 - sin^2 A = cos^2 A }

= > [ ( 1 - sinA ) / cosA ]^2

= > ( 1 / cosA - sinA / cosA )^2

= > ( secA - tanA )^2

Hence proved.