Question

Pls solve this question very fast question starts from the first image

Answer 1

Answer:

sinQ=cos(3Q-30)

cos(90-Q)=cos(3Q-30)

90-Q=3Q-30

4Q=120

Q=30

ii) Q=30

TANQ=P/B

Tan 30=AB/BC

1/√3=200/BC

BC=200√3