Question

Pls solve this question, which is frm trigonometry:)

Answer 1

Given, cos 45/(sec 30 + cosec 30)

= (1/√2)/(2/√3 + 2)                         {since cos 45 = 1/√2, sec 30 = 2/√3, cosec 30 = 2}

= (1/√2)/{(2 + 2√3)/√3}

= (√3/√2)/(2 + 2√3)

= √3/{√2*(2 + 2√3)}

= √3/(2√2 + 2√3*√2)

= √3/(2√2 + 2√6)

So, cos 45/(sec 30 + cosec 30) = √3/(2√2 + 2√6)