Question

Pls Solve This Question With your Own Solution Pls don't copy from others sites otherwise u will be reported​

Answer 1

Answer:

x=2 or x=1

Step-by-step explanation:

$( {2}^{x - 1} )^{2} - 3. {2}^{x - 1} + 2 = 0 \\ ( {2}^{x - 1} )^{2} - {2}^{x - 1} - 2.{2}^{x - 1} + 2 = 0 \\ ( {2}^{x - 1} )( {2}^{x - 1} - 1) - 2( {2}^{x - 1} - 1) = 0 \\ ( {2}^{x - 1} - 2)( {2}^{x - 1} - 1) = 0$

$( {2}^{x - 1} ) = 2 \: or \: ( {2}^{x - 1} ) = 1$

x=2 or x=1