Pls solve this someone
pls help me out pls pls pls pls solve this problem pls help me someone pls solve
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1
what's the shape of box ???
let me assume it as cube ..
I) each dimension is doubled
original TSA = 6a^2
now a is doubled = 2a
new TSA = 6(2a)^2
=6*4*a^2
4(6a^2
the area will be 4 times..
II) Each dimension is tripled
original TSA = 6a^2
now a is tripled = 3a
new TSA = 6(3a)^2
= 6*9a^2
9(6a^2)
the area will be 9 times.
hope it helps
let me assume it as cube ..
I) each dimension is doubled
original TSA = 6a^2
now a is doubled = 2a
new TSA = 6(2a)^2
=6*4*a^2
4(6a^2
the area will be 4 times..
II) Each dimension is tripled
original TSA = 6a^2
now a is tripled = 3a
new TSA = 6(3a)^2
= 6*9a^2
9(6a^2)
the area will be 9 times.
hope it helps
Answered by
6
When the dimension is doubled (which is 2 times)
The area is increased (2)² = 4 times
When the dimension is tripled (which is 3 times)
The area is increased (3)² = 9 times
Therefore when the dimension is increased to n time
The area is then increased n² times
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