Math, asked by mail2drsarita, 11 months ago

Pls solve this!! step by step will marked as brainliest pls do Q1 for meh

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Answered by jayantbittoo
0

you must know the identity for this question

A^3+B^3+C^3=3ABC------------------(1)

if A+B+C=0

A=a^2-b^2,B=b^2-c^2,C=a^2-b^2

A+B+C=0

as ----- a^2-b^2+b^2-c^2+c^2-a^2=0 ( you must be able to see it )

(a^2-B^2)^3+(b^2-C^2)^3+(a^2-c^2)^3=3(a^2-b^2)(b^2-c^2)(a^2-c^2)----from(1)

= a+c(a-c)(b+c)(b-c)(b+a)(b-a)

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