Pls solve this sum..i m confused
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given BD = CE on adding DE on both sides
BD+DE = CE + DE => BE = CD
Now consider ∆le BGE & ∆le DFC
angle(GBD) = angle(FDC) as they are corresponding angles of parallel lines
BE = CD Proved above
angle(GEB) = angle(FCD) as they are corresponding angles of parallel lines
=> ∆ BGE Is congruent to ∆ DFC
this implies by CPCT:
BG = DF
CF = EG
HENCE PROVED.....
sanyuktanikkop1grf9:
But corresponding angles in a straight line are not equal..they are Supplementry right?...and also u didn't give me Which Formula Of congruency did u use
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