Question

pls solve this ( tomorrow is exam )

Answer 1

14 ans; by phythagoras therom
square of AB - Squre of AD= square of BD
=400-256
=144
=square root of 144
=12=BD

square of AC - Square of AD= square of DC
=1156-256
=900
=square root of 900
=30=DC

BD+DC=BC
12+30=42


16ans;by phy. thm
square of AB - square of AD= Square of BD
=625-400=255
square root of 225 = 15 = BD

BC - BD = DC
36-15=21
now,
 square of AD = Square of DC= square of AC
400+441=841
squareroot of 841=29
therefore AC= 29


Answer 2

15.DC=34×34-16×16=1156-256=900
DC=900÷3÷3÷5÷5÷2÷2
DC=30cm
BD=20×20-16×16=400-256=144
BD=144÷12÷12
BD=12cm
BC=DC+BD=30+12=42ans

16.DB=25×25-20×20=625-400=225
DB=225÷15÷15
DB=15cm
DC=36-15=21
AC=21×21+20×20=441+400=841
AC=841÷29÷29
AC=29ans