pls solve this trigonometry question
Attachments:
Answers
Answered by
1
Hey !!!
tanA =√3 /4 -√3
tanB = √3/4+√3
•°•tan (A - B) = tanA - tanB /1 + tanA×tanB
Hence , put the value of tanA and tanB
√3/4-√3 - √3/4+√3
----------------------------
1 +√3×√3/(4² - √3²)
√3(4+√3) - √3(4 -√3)
------------------------------
4² - (√3)² + 3
4√3 + 3 - 4√3+ 3
---------------------------
16 - 3 + 3
6/16 = 0.375 Answer ✔
✔Here prooved tan(A - B ) = 0.375
_____________________________
Hope it helps you !!
@Rajukumar111
tanA =√3 /4 -√3
tanB = √3/4+√3
•°•tan (A - B) = tanA - tanB /1 + tanA×tanB
Hence , put the value of tanA and tanB
√3/4-√3 - √3/4+√3
----------------------------
1 +√3×√3/(4² - √3²)
√3(4+√3) - √3(4 -√3)
------------------------------
4² - (√3)² + 3
4√3 + 3 - 4√3+ 3
---------------------------
16 - 3 + 3
6/16 = 0.375 Answer ✔
✔Here prooved tan(A - B ) = 0.375
_____________________________
Hope it helps you !!
@Rajukumar111
Similar questions