Question

pls solve this urgently...​ then answer is 0....and

thank u.

Answer 1

GOOD MORNING

t = √x + 3

( t - 3 ) = √x

SQUARING ON BOTH SIDES WE HAVE

( t² + 9 - 6t ) = x

DIFFERENTIATE BOTH SIDES W.R.T t

2t - 6 = dx/dt

v = 2t - 6 { dx/dt = v }

v = 0

2t - 6 = 0

t = 3

Now, put value of t in given Equation we have

3 = √x + 3

√x = 0

SQUARING ON BOTH SIDES WE GET

x = 0

So, At time t = 3sec Displacement of that particle is zero.