Chemistry, asked by Anonymous, 11 months ago

pls solve this using OXIDATION NUMBER METHOD

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Answered by ayushupadhyay0307
1

Answer:

Explanation:

Let us Balance this Equation by the concept of the Oxidation number method.

∴ General Steps ⇒

Step 1. First Write the Given Redox Reaction.

MnO₄ + I⁻ -------- MnO₂ + I₂

Step2. Identify Oxidation and Reduction half Reaction.

MnO₄ ------ MnO₂ [Reduction]

I⁻ --------I₂ [Oxidation]

Step3. Balance the atoms undergoing change in the Oxidation number.

∴ MnO₄ -------- MnO₂ [Change of 4 units].

2I⁻ ---------- I₂ [Change of 2 units]

Step 4 . Multiply 1st equation by 1 and second equation by 2.

∴ MnO₄ -------- MnO₂ and 4I⁻ ---------- 2I₂

Step 5. Now, Add both the equations,

∴ 4I⁻ + MnO₄ ---------- I₂ + MnO₂

Step 6. Now, Balance the charges by adding water and Hydrogen ions.

∴ 4I⁻ + MnO₄ + 2H₂O ---------- I₂ + MnO₂ + 4OH⁻

This is the Required balanced Chemical Equation.

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